In March, I blogged about a TV documentary about the Kryptos sculture produced by CNN. It has now aired and is available on Youtube.

Frequent readers of this blog certainly know Elonka Dunin, the world’s leading expert on the Kryptos sculpture and it’s encrypted inscription. Elonka maintains a website titled Famous Unsolved Codes and Ciphers, which lists about a dozen unsolved mysteries from the world of cryptology and ancient languages. This page is the oldest of its kind.

Schmeh

Contrary to this blog, Elonka’s page also covers non-cryptologic language mysteries, such as the Indus script and the Rongorongo script. All other topics mentioned in Elonka’s list have been discussed on this blog before – including the Voynich manuscript, the Zodiac Killer, the Dorabella cipher, and, of course, part 4 of the Kryptos inscription.

 

Ask me anything

Yesterday, Elonka hosted a so-called “Ask me anything” (AMA) on Reddit. An AMA is an online chat everybody can take part in. The rules of an AMA are quite simple: every participant can ask any question he or she likes; the host gives answers.

The minutes of Elonka’s AMA session are available on Reddit. Altogether, there were 747 comments by Elonka and the participants. It comes as no surprise that many of the questions asked were about Kryptos and other crypto mysteries. Here are a few examples:

Rqoo51: {…] how are we sure the guy that designed the [Kryptos] puzzle didn’t mess up when encrypting the message and it in fact won’t translate back to plaintext? Like has someone else in the CIA being told the solution?

Elonka: My belief is that he intended it to be solved, with an English plaintext that’s 97 characters long (and has BERLINCLOCK at the 64th position). However, to my knowledge, no one has ever tested his solution, so it’s entirely possible that it has some mistake or impossible-to-reproduce method. I think our best shot at solving it will be to try to replicate his method of pencil-and-paper matrices that he used for K1-K3, and then try to think like an artist, what might he have done to “make it harder”, like by folding a page, flipping it over backwards, or something like that.

veggiekid23: What’s something no one has asked about yet that you really want to talk about?

Elonka: One other thing, the cipher that I found on the Friedman Tombstone at Arlington National Cemetery, I was very proud of that!

YVX: What is your favorite code/cypher and why?

Elonka: Well, I’d love to get Kryptos K4 off my plate! It it were solved, I’d probably turn my attention to Edward Elgar’s Dorabella Cipher, I think that’s the next one most likely to be solved, as opposed to being a deliberate hoax.

domino7: What are the odds that the various parts of Kryptos, when decoded, will in turn be part of a fifth meta-code?

Elonka: Very high. Sanborn himself has said that even once K4 is solved, there will be a further mystery to be solved. He has said many times that one of the points of artwork is to hold someone’s attention. If everything about it can be absorbed rapidly, with nothing new to learn, then he feels that the artist has failed.

 

A Kryptos TV documentary on CNN

In March 2019, I published a blog post about the prodution of a TV documentary about Kryptos. It comes as no surprise that Elonka took a leading role in it. Among the other people shown in this program is blog reader Richard SantaColoma from New York State. A few days ago, the documentary aired on CNN. It has since been made available on YouTube. To my regret, it lasts only a little more than six minutes. Here it is:

This video has already received over 1.1 million hits on YouTube. That’s a lot.

When blog reader Michael Hörenberg watched this video, he found the following quote of Kryptos creator Jim Sanborn especially interesting (4:25): “So if one invested a lot of time in the environment around KRYPTOS that would be kind of silly.” If this statement is correct, the search for clues at the sculpture and around it – a difficult task, as Kryptos is not accessible to the public – is a waste of time. More insights in the Kryptos mystery might be available soon: Jim Sanborn recently announced to give a new clue.


Further reading: The Top 50 unsolved encrypted messages: 4. Kryptos

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Kommentare (10)

  1. #1 Michael BGNC
    Lake Constance
    12. Juli 2019

    DYAHR is important, but Sanborn said this already, and you have not to be present on the CIA ground. It´s on his replica.

  2. #2 Muko
    Kryptos
    12. Juli 2019

    BLETCHLEY PARK, BOMBE, ALAN TURING. Keep in mind these words.

  3. #3 zorroo99
    25. Juli 2019


    plain- BETWEENSUBT LESHaDINGa NDTHEABSEN CEOFlIGHTl
    layer1 PALIMpSESTp ALIMpSESTp ALIMpSESTp ALIMpSESTp
    layer2 XTSESpMILAp TSESpMILAp TSESpMILAp TSESpMILAp

    index KRYPTOS + ABCDEFG

  4. #4 Marc
    31. Juli 2019

    QOBKRUOXOGH
    QQSSSSSWEST
    KEYQUIZRQAD (KEY QU IS ROAD)

    iA KRYPTOSABCDEFGHIJLMNQUVWXZ
    iB ROADBCEFGHIJKLMNPQSTUVWXYZ

    NCEOFILLUSION
    PALIMPSESTPAL iA
    TPALIMPSESTPA iA
    VJYQTMKYRDMFD

    L + S + P = K

    GROUNDTOA
    ABSCISSAA iB
    AABSCISSA iB
    QCRTBJDFH

    O + S + B = R

    Pay attention to the double letters, it’s used to find out the key.

  5. #5 Marc
    4. August 2019

    Noch ein anderer Gedanke.

    Maskierung für den Klartext:
    1. Alle Es entfernen
    2. Alle As durch Es ersetzen
    3. Den ersten Buchstaben jedes Doppelbuchstabens durch A ersetzen

    (1 und 2 ergeben sich durch Fehler in K3)

    Schlüssellänge Vigenère = 10
    Blockgröße für Transposition = 8

    PALIMPSE STPALIMP
    12345678 12345678
    XLAYERTW O

    Entschlüsseln mit 564738291.

    PALIMPSE STPALIMP
    12345678 12345678
    OTEAXLYR W

    Den Block um eine Position nach rechts verschieben,
    das W behält seine Position.

    PALIMPSE STPALIMP
    12345678 12345678
    ROTEAXLY W

    Das X wieder entfernen.

    PALIMPSE STPALIMP
    12345678 12345678
    ROTEALYW

    Den Klartext nach den o.g. Regeln demaskieren.

    ROTALLYW = ROT ALL Y W

    Eventuell wird hier der Text zweimal mit Vigenère verschlüsselt, um zu ermöglich,
    dass der Empfänger den Schlüssel selbst rekonstruieren kann, ohne ihn vorher zu
    kennen. Hierfür könnte ein zweites Alphabet für die Indizierung der
    Schlüsselbuchstaben genutzt worden sein. Dann wäre allerdings die Frage, wann
    genau die beiden Substitutionen ausgeführt werden. Die Entschlüsselung würde hierbei
    blockweise erfolgen und das X von Block zu Block wandern. Die Entfernung der Es ist
    dabei allerdings problematisch, da der Empfänger hier selbst herumrätseln müsste und
    sich an einigen Positionen im Klartext keine eindeutige Lösung mehr ergeben könnte.
    Vielleicht haben die beiden Teile, die man mit einer einfachen Cäsar-Verschiebung
    lösen kann (KEHSARETEN + THEWAXY), etwas mit den herausgenommenen Es zu tun,
    wer weiß. Zumindest passt diese Aufteilung in 8 Buchstaben pro Block zu K4.

  6. #6 Juha
    12. August 2019

    Hindi words suits fairly well (using Google)…but could the Kryptos fourth riddle be so simple?

    ob=when
    kr=k
    uo = come on
    xo = so
    ghul = dissolves
    bs=B.S.
    ol = all
    I (hi) =Mr.
    fb=FB
    bw =bava
    fl= result/ (multiple word choices with Google)
    rv= noise
    qq= that
    prn= but
    gk= Guck… ( gks= guckus)
    ss
    ot= veil (oats)
    wt= vat
    qs= tight
    j
    qs= tight
    se= from
    kz= Qaz
    zw=Barley
    at=e
    j=j
    kl= tomorrow
    ud = fly
    ia= Mr.
    w=and
    i=Mr.
    n = not
    f=f
    bn=become
    y=this
    pv= festival
    tt= coast
    mz=fun
    fb= become
    gd= the citadel
    k=a
    zx=Jus
    tj=taj
    cd= height
    ig= gig
    ku= to
    HUAUEKCAR= happened

  7. #7 Marc
    25. August 2019

    @Juha
    QKR Jentral Untelligence Hgency

    intRerupt

    wonderful 😉

  8. #8 Juha
    Hamina
    23. September 2019

    This fits fairly well, but hardly is the right one…

    K4:
    There is four road yard to officeooir fo zxyjn to give a stick don´t worry yes berlin clock flyxt doesn’t work I don´t mind

  9. #9 Marc
    18. Dezember 2019

    13 days remaining, is the last clue supposed to be a Christmas gift? Who knows!

  10. #10 Richard Bean
    Brisbane
    2. Januar 2020

    No. Since November 2014, Sanborn has asked for a $50 fee to check any solution, so he has a strong commercial incentive not to release another useful clue.

    (At the October 2015 Kryptos dinner, according to Elonka, he noted that one person had contacted him “about a hundred times”; at the March 2019 sushi lunch, he said people contact him daily.)