A crypto book published in 1939 contains an excercise cryptogram. Many have tried to solve it, but the solution is still unknown.

I can hardly believe it. I have been a crypto history blogger for over four years now with about 750 posts published, but so far I have not blogged about a quite well-known unsolved crypto mystery: the D’Agapeyeff cryptogram.

The D’Agayeff cryptogram is mentioned in many “top ten unsolved ciphers” list, for instance the following one presented in a video on YouTube. MysteryTwister C3, a web portal dedicated to codebreaking puzzles, has a D’Agapeyeff challenge in the X section (X stands for unsolved). Here’s the English version, here’s the German one. I am the author of this challenge, by the way.

Seven years after I wrote this MTC3 challenge, it is now high time to cover the D’Agapeyeff cryptogram on Klausis Krypto Kolumne.

 

The challenge

In 1939 the Russian-born Briton Alexander D’Agapeyeff published a book named Codes and Ciphers.

DAgapeyeff-Codes-Ciphers

When looking for information about a vintage crypto book it is always a good idea to check Tobias Schrödels crypto bibliography, which lists no less than 538 books. In fact, D’Agapeyeff’s Codes and Ciphers can be found there. According to Tobias, Codes and Ciphers is not one of the top books about the subject, but it’s an entertaining read and it renders a good summary of the most important encryption methods of the time.

D’Agapeyeff’s Codes and Ciphers is best remembered for a ciphertext printed on the last page. It was meant as an excercise. Here it is:

Agapeyeff-cryptogram

It soon became clear that this challenge was not an easy one. In fact, nobody at all could decipher this message. Meanwhile many professional and hobby codebreakers have tried to solve it, but to no avail.

 

Basic analysis

Here’s a transcription of the challenge:

75628 28591 62916 48164 91748 58464 74748 28483 81638 18174
74826 26475 83828 49175 74658 37575 75936 36565 81638 17585
75756 46282 92857 46382 75748 38165 81848 56485 64858 56382
72628 36281 81728 16463 75828 16483 63828 58163 63630 47481
91918 46385 84656 48565 62946 26285 91859 17491 72756 46575
71658 36264 74818 28462 82649 18193 65626 48484 91838 57491
81657 27483 83858 28364 62726 26562 83759 27263 82827 27283
82858 47582 81837 28462 82837 58164 75748 58162 92000

As adjacent columns are formed alternately from 67890 and 12345 characters respectively, it makes sense to write the message as a sequence of pairs:

75 62 82 85 91 62 91 64 81 64 91 74 85 84 64 74 74 82 84 83 81 63 81 81 74
74 82 62 64 75 83 82 84 91 75 74 65 83 75 75 75 93 63 65 65 81 63 81 75 85
75 75 64 62 82 92 85 74 63 82 75 74 83 81 65 81 84 85 64 85 64 85 85 63 82
72 62 83 62 81 81 72 81 64 63 75 82 81 64 83 63 82 85 81 63 63 63 04 74 81
91 91 84 63 85 84 65 64 85 65 62 94 62 62 85 91 85 91 74 91 72 75 64 65 75
71 65 83 62 64 74 81 82 84 62 82 64 91 81 93 65 62 64 84 84 91 83 85 74 91
81 65 72 74 83 83 85 82 83 64 62 72 62 65 62 83 75 92 72 63 82 82 72 72 83
82 85 84 75 82 81 83 72 84 62 82 83 75 81 64 75 74 85 81 62 92 00 0

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Kommentare (8)

  1. #1 George Lasry
    18. Juni 2017

    I recently I did some in-depth research about the most common hypothesis, which is transposition combined with substitution (two digits -> one letter), checking all possible transposition schemes (row tr., column tr., row major/column major read/write etc…). I can confirm with a high degree of confidence that d’Agapayeff cipher is not of that type.

  2. #2 Klaus Schmeh
    18. Juni 2017

    Bart Wenmeckers via Facebook:

    Ah this is very interesting Klaus. I have not seen this one before in detail. Thank you for posting. I already see some details which make me want to investigate. 🙂

  3. #3 anderer Michael
    18. Juni 2017

    Maybe it was a early hoax, only a joke. Don’t forget please, he was an English man, and he was born in Russia.

  4. #4 Narga
    20. Juni 2017

    @GeorgeLasry: Did you see this blog-article from Nick Pelling here? https://ciphermysteries.com/2017/03/05/new-clue-dagapeyeff-challenge-cipher

    Perhaps d’Agapeyeff really just applied the encryption technique wrong and that’s what makes it so difficult to decrypt?

  5. #5 George Lasry
    20. Juni 2017

    Interesting (Double Transposition clue)…. worth a trial

    A mistake in encryption seems very likely. Another option which has been mentioned (by Jim Gillogly) is a botched Mirabeau encryption.

  6. #6 Thomas Ernst
    Latrobe
    4. Juli 2017

    Two simple observations, which probably are not new: the plain text of d’Agapeyeff’s earlier Polybios example – see wiki – did not end on a final fiver, but on only three letters (EDC). With a total of 395 individual numbers in the “Challenge”, I assume that one or three of the final “0” indeed are “nulls”, but do not know what underlying encipherment rule makes them so. – Secondly, I think that this, too, is a mono-alphabetic Polybios, but that the pairs simply are arranged differently. It would be worthwhile to write out different pairs, 1-3, for example, or every fourth letter (also considering backward writing), whathaveyou, till one comes up with a suitable frequency count. Furthermore, there exists the possibility that the plain text is in another language than English, such as Russian or Latin.

  7. #7 Abhishek Ramchandran
    9. Juli 2017

    Perhaps he used a Beale cipher where each number corresponded to a page number, line number, word number, letter position in his book! I have a copy of Codes and Ciphers with me, I could try investigating.

  8. #8 Christof Rieber
    Vienna
    7. November 2020

    This hopefully is the correct transcription of bigrams into – still encrypted – cipher text:

    abcdebefgfehdifhhcijgkgghhcbfajcieahljaaamkllgkgadaafbcndhkcahjglgidfdfddkcobjbggogfkacgfjkcdgkkkphgeeikdilfdlbqbbdedeheoaflarljbfhgcibcfegmlbfiiejdheglohjjdcjfboblbjanokccoojcdiacgjoibcjagfahdgbn

    Remarkably often double letters/bigrams do occur.